Consider the following circuit
The flip-flops are positive edge triggered D FFs. Each state is designated as a two bit string Q0Q1. Let the initial state be 00. The state transition sequence is:
Explanation: Q0 will toggle in every cycle because Q0‘ (Q0 complement) is fed as input to the D0 flip flop.
For the D1 flip flop, D1 = Q0 ⊕ Q1‘ , i.e., Q0 XOR Q1‘.
So, the bit pattern Q0 Q1 will be :
Q0 Q1 0 0 1 1 0 1 1 0 0 0 . . . . . .
So, D would be the correct choice.
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