C++ | Virtual Functions | Question 13

#include <iostream> 
using namespace std; 
   
class A 
{ 
public: 
    virtual void fun() { cout << "A::fun() "; } 
}; 
   
class B: public A 
{ 
public: 
   void fun() { cout << "B::fun() "; } 
}; 
   
class C: public B 
{ 
public: 
   void fun() { cout << "C::fun() "; } 
}; 
   
int main() 
{ 
    B *bp = new C; 
    bp->fun(); 
    return 0; 
} 

(A) A::fun()
(B) B::fun()
(C) C::fun()

Answer: (C)

Explanation: The important thing to note here is B::fun() is virtual even if we have not uses virtual keyword with it.

When a class has a virtual function, functions with same signature in all descendant classes automatically become virtual. We don’t need to use virtual keyword in declaration of fun() in B and C. They are anyways virtual.

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