C++ | Virtual Functions | Question 13
#include <iostream>using namespace std; class A{public: virtual void fun() { cout << "A::fun() "; }}; class B: public A{public: void fun() { cout << "B::fun() "; }}; class C: public B{public: void fun() { cout << "C::fun() "; }}; int main(){ B *bp = new C; bp->fun(); return 0;} |
(A) A::fun()
(B) B::fun()
(C) C::fun()
Answer: (C)
Explanation: The important thing to note here is B::fun() is virtual even if we have not uses virtual keyword with it.
When a class has a virtual function, functions with same signature in all descendant classes automatically become virtual. We don’t need to use virtual keyword in declaration of fun() in B and C. They are anyways virtual.
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