Consider the following C declaration
Assume that objects of the type short, float and long occupy 2 bytes, 4 bytes and 8 bytes, respectively. The memory requirement for variable t, ignoring alignment considerations, is (GATE CS 2000)
(A) 22 bytes
(B) 14 bytes
(C) 18 bytes
(D) 10 bytes
Explanation: Short array s will take 10 bytes as size of short is 2 bytes.
When we declare a union, memory allocated for the union is equal to memory needed for the largest member of it, and all members share this same memory space. Since u is a union, memory allocated to u will be max of float y(4 bytes) and long z(8 bytes). So, total size will be 18 bytes (10 + 8).
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