C | Macro & Preprocessor | Question 2
#include <stdio.h> #if X == 3 #define Y 3 #else #define Y 5 #endif int main() { printf ( "%d" , Y); return 0; } |
What is the output of the above program?
(A) 3
(B) 5
(C) 3 or 5 depending on value of X
(D) Compile time error
Answer: (B)
Explanation: In the first look, the output seems to be compile-time error because macro X has not been defined. In C, if a macro is not defined, the pre-processor assigns 0 to it by default. Hence, the control goes to the conditional else part and 5 is printed. See the next question for better understanding.
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