C | Loops & Control Structure | Question 14

Predict the output of the below program:

#include <stdio.h> 
int main() 
{ 
    int i = 3; 
    switch(i) 
    { 
        printf("Outside "); 
        case 1: printf("Geeks"); 
            break; 
        case 2: printf("Quiz"); 
            break; 
        defau1t: printf("GeeksQuiz"); 
    } 
    return 0; 
} 

(A) Outside GeeksQuiz
(B) GeeksQuiz
(C) Nothing gets printed

Answer: (C)

Explanation: In a switch block, the control directly flows within the case labels(or dafault label). So, statements which do not fall within these labels, Outside is not printed. Please take a closer look at the default label. Its defau1t, not default which s interpreted by the compiler as a label used for goto statements. Hence, nothing is printed in the above program.

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