Open In App
Related Articles

C | Loops & Control Structure | Question 10

Improve
Improve
Improve
Like Article
Like
Save Article
Save
Report issue
Report
# include <stdio.h>
int main()
{
   int i = 0;
   for (i=0; i<20; i++)
   {
     switch(i)
     {
       case 0:
         i += 5;
       case 1:
         i += 2;
       case 5:
         i += 5;
       default:
         i += 4;
         break;
     }
     printf("%d  ", i);
   }
   return 0;
}

                    
(A) 5 10 15 20 (B) 7 12 17 22 (C) 16 21 (D) Compiler Error

Answer: (C)

Explanation: Initially i = 0. Since case 0 is true i becomes 5, and since there is no break statement till last statement of switch block, i becomes 16. Now in next iteration no case is true, so execution goes to default and i becomes 21. In C, if one case is true switch block is executed until it finds break statement. If no break statement is present all cases are executed after the true case. If you want to know why switch is implemented like this, well this implementation is useful for situations like below.
 switch (c)
 {
    case 'a':
    case 'e':
    case 'i' :
    case 'o':
    case 'u':
      printf(" Vowel character");
      break;
    default :
      printf("Not a Vowel character");; break;
  }

Last Updated : 06 Feb, 2013
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads