Aptitude | Trigonometry & Height and Distances | Question 5

The least value of 2sin^{2}θ + 3cos^{2}θ**(A)** 1/3**(B)** 4/3**(C)** 2**(D)** 3/4**Answer:** **(C)****Explanation:** = 2sin^{2}θ + 2cos^{2}θ + cos^{2}θ

=2(sin^{2}θ + cos^{2}θ) + cos^{2}θ ; (by putting sin^{2}θ + cos^{2}=1)

= 2 + cos^{2}θ ;(the minimum value of cos^{2}θ=0)

= 2 + 0 = 2

Quiz of this Question

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