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Aptitude | Trigonometry & Height and Distances | Question 5
  • Difficulty Level : Medium
  • Last Updated : 19 May, 2016
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The least value of 2sin2θ + 3cos2θ
(A) 1/3
(B) 4/3
(C) 2
(D) 3/4


Answer: (C)

Explanation: = 2sin2θ + 2cos2θ + cos2θ

=2(sin2θ + cos2θ) + cos2θ ; (by putting sin2θ + cos2=1)

= 2 + cos2θ ;(the minimum value of cos2θ=0)

= 2 + 0 = 2

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