The least value of 2sin2θ + 3cos2θ
Explanation: = 2sin2θ + 2cos2θ + cos2θ
=2(sin2θ + cos2θ) + cos2θ ; (by putting sin2θ + cos2=1)
= 2 + cos2θ ;(the minimum value of cos2θ=0)
= 2 + 0 = 2
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