What will be the output of the below C program?
#include <stdio.h>
int main()
{
int x = 2;
do{
++x;
printf("%d", x);
} while(--x <= 2);
return 0;
}
|
(A) Runtime Error
(B) 2
(C) 3
(D) Infinite Loop
Answer: (D)
Explanation: As the value of x is incremented(++x) and then decremented(–x), hence no change in the value of x will occur and it will be as 2.
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