# Aptitude | Progressions | Question 8

Find the sum of series: 1/3, 1/9, 1/27, 1/81……………..**(A)** 1/2**(B)** 1/3**(C)** 1/4**(D)** 1/6**Answer:** **(A)****Explanation:**

The given series is an infinite GP, whose sum is given by Sn=a/(r-1)

Where,

a=first term of series,

r=common ratio.

Therefore,

Sn=(1/3)/(1-1/3)

Sn=1/2