StrictMath IEEEremainder() Method in Java

The Java.lang.StrictMath.IEEEremainder() is an inbuilt method of StrictMath class which is used to perform the remainder operation on given two arguments as prescribed by the IEEE 754 standard. The remainder value is mathematically equal to , where rem is the mathematical integer closest to exact mathematical value of the quotient , and when two mathematical integers are equally close to , and n is an even integer. It gives rise to two special results: 

• Its sign is same as the sign of the first argument when the remainder is zero.
• It returns NaN when either argument is NaN, or num1 is infinite, or num2 is positive or negative zero.
• The result is same as the num1 when num1 is finite and the num2 is infinite.

Syntax:

public static double IEEEremainder(double num1, double num2)

Parameters: The method accepts two parameters : 

• num1: This is of double type which is the dividend.
• num2 This is also of double type which is the divisor.

Return Value: The method returns the remainder when num1 is divided by num2.
Examples :

Input: 
num1 = 100.61d
num2 = 5.32d

Output: -0.47000000000000597

Below programs illustrate the Java.lang.StrictMath.IEEEremainder() method: 
Program 1: 

java

// Java program to illustrate the
// Java.lang.StrictMath.IEEEremainder()
import java.lang.*;

public class Geeks {

    public static void main(String[] args)
    {

        double num1 = 5651.51d, num2 = 61.79d;

        // It  returns the remainder value
        double remain_val = StrictMath.IEEEremainder(num1, num2);
        System.out.println("Remainder value of "+num1+" & "+num2
                                            +" = " + remain_val);
    }
}

Output:

Remainder value of 5651.51 & 61.79 = 28.620000000000296

Program 2: 

java

// Java program to illustrate the
// Java.lang.StrictMath.IEEEremainder()
import java.lang.*;

public class Geeks {

    public static void main(String[] args)
    {
        /* Here  num1 is finite and num2 is infinite so
     the result is the same as the num1 */
        double num1 = 70.55d, num2 = (1.0) / (0.0);

        double remain_val = StrictMath.IEEEremainder(num1, num2);
        System.out.println("Remainder value of "+num1+" & "+num2
                                            +" = " + remain_val);
    }
}

Output:

Remainder value is = 70.55