StrictMath exp() Method in Java

All methods of java.lang.StrictMath class : Set 1, Set 2
The java.lang.StrictMath.exp() is an inbuilt method in Java is used to return a Euler number raised to the power of the specified double value. It gives rise to three special results: 

• The result is positive infinity when the given argument is positive infinity.
• The result is positive zero when the argument is negative infinity.
• The result is NaN when the given argument is NaN.

Syntax : 

public static double exp(double num)

Parameters: This method accepts one parameter num which is of double type which is the exponent to raise e to.
Return Value: The method returns the value e^num, where e is the base of the natural logarithms.
Examples:

Input: num = 7
Output: 1096.6331584284585

Input: num = (1.0 / 0.0)
Output: Infinity

Below programs illustrate the java.lang.StrictMath.exp() method: 
Program 1:

java

// Java program to illustrate the
// java.lang.StrictMath.exp()
import java.lang.*;

public class Geeks {

    public static void main(String[] args)
    {

        double num1 = 0.0, num2 = (1.0 / 0.0);
        double num3 = 4;

        // Returns Euler's number e raised to the given power
        double expValue = StrictMath.exp(num1);
        System.out.println("The exp value of "+
                         num1+" = " + expValue);

        expValue = StrictMath.exp(num2);
        System.out.println("The exp value of "+
                         num2+" = " + expValue);

        expValue = StrictMath.exp(num3);
        System.out.println("The exp value of "+
                         num3+" = " + expValue);    }
}

Output:

The exp value of 0.0 = 1.0
The exp value of Infinity = Infinity
The exp value of 4.0 = 54.598150033144236

Program 2: 

java

// Java program to illustrate the
// java.lang.StrictMath.exp()
import java.lang.*;

public class Geeks {

    public static void main(String[] args)
    {

        double num1 = -0.0, num2 = (1.0 / 0.0);
        double num3 = 14;

        // Returns Euler's number e raised to the given power
        double expValue = StrictMath.exp(num1);
        System.out.println("The exp value of "+
                         num1+" = " + expValue);

        expValue = StrictMath.exp(num2);
        System.out.println("The exp value of "+
                         num2+" = " + expValue);

        expValue = StrictMath.exp(num3);
        System.out.println("The exp value of "+
                         num3+" = " + expValue);
    }
}

Output:

The exp value of -0.0 = 1.0
The exp value of Infinity = Infinity
The exp value of 14.0 = 1202604.2841647768