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StrictMath floor() Method in Java

The java.lang.StrictMath.floor() is the inbuilt method which returns the largest double value, less than or equal to the given argument and is equal to the integer value. 

Syntax :  



public static double floor(double num)

Parameters: This method accepts one parameter num which is of double type .
Return Value : The method returns the largest value which, closest to positive infinity, less than or equal to the argument and equal to an integer.
Examples :  

Input: num = 9.6
Output: 9.0

Input: num = -7.8
Output: -8.0

Below programs illustrate the java.lang.StrictMath.floor() method: 
Program 1:  






// Java program to illustrate the
//java.lang.StrictMath.floor()
 
import java.lang.*;
 
public class Geeks {
 
public static void main(String[] args) {
 
    double num1 = 7.8, num2 = 1.4 ;
 
    double fValue = StrictMath.floor(num1);
    System.out.println("The floor value of "+
                             num1+" = " + fValue);
 
    fValue = StrictMath.floor(num2);
    System.out.println("The floor value of "+
                             num2+" = " + fValue);
}
}

Output: 
The floor value of 7.8 = 7.0
The floor value of 1.4 = 1.0

 

Program2: 




// Java program to illustrate the
//java.lang.StrictMath.floor()
 
import java.lang.*;
 
public class Geeks {
 
public static void main(String[] args) {
 
    double num1 = -7.8, num2 = -1.4 ,num3 = 0.1 ;
 
    double fValue = StrictMath.floor(num1);
    System.out.println("The floor value of "+
                             num1+" = " + fValue);
 
    fValue = StrictMath.floor(num2);
    System.out.println("The floor value of "+
                             num2+" = " + fValue);
 
    fValue = StrictMath.floor(num3);
    System.out.println("The floor value of "+
                             num3+" = " + fValue);
 
}
}

Output: 
The floor value of -7.8 = -8.0
The floor value of -1.4 = -2.0
The floor value of 0.1 = 0.0

 


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