What is the output of following program?
#include<stdio.h> void swap(char *str1, char *str2)
{ char *temp = str1;
str1 = str2;
str2 = temp;
} int main()
{ char *str1 = "Geeks";
char *str2 = "Quiz";
swap(str1, str2);
printf("str1 is %s, str2 is %s", str1, str2);
return 0;
} |
(A) str1 is Quiz, str2 is Geeks
(B) str1 is Geeks, str2 is Quiz
(C) str1 is Geeks, str2 is Geeks
(D) str1 is Quiz, str2 is Quiz
Answer: (B)
Explanation: The above swap() function doesn’t swap strings. The function just changes local pointer variables and the changes are not reflected outside the function. See following for more details.