C
#include<stdio.h>int main()
{ char str[] = \"GeeksQuiz\";
printf(\"%s %s %s \", &str[5], &5[str], str+5);
printf(\"%c %c %c \", *(str+6), str[6], 6[str]);
return 0;
} |
(A)
Runtime Error
(B)
Compiler Error
(C)
uiz uiz uiz u u u
(D)
Quiz Quiz Quiz u u u
Answer: (D)
Explanation:
The program has no error. All of the following expressions mean same thing &str[5] &5[str] str+5 Since compiler converts the array operation in pointers before accessing the array elements, all above result in same address. Similarly, all of the following expressions mean same thing. *(str+6) str[6] 6[str]
Quiz of this Question
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