Ram and his wife Sita both have five friends each. Ram has 2 boys and 3 girls. Sita has 3 boys and 2 girls. In how many maximum number of different ways can they invite 2 boys and 2 girls such that two of them are Ram’s friend and two are Sita’s friend?
(A) 46 ways
(B) 42 ways
(C) 40 ways
(D) 36 ways
Answer: (A)
Explanation: Selection can be done like that
i) 2 boys from Ram’s friends and 2 girls from his wife Sita’s friends OR
ii) 1 boy and 1 girl from Ram’s friends and 1 boy and 1 girl from Sita’s friends OR
iii) 2 boys from his wife Sita’s friends and 2 girls from Ram’s friends
Total number of ways = 2C2.2C2 + 3C1 x 2C1 x 3C1 x 2C1 + 3C2.3C2
= 1 + 36 + 9
= 46 ways
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