| | Question 2

Find the number of trailing zeroes in 155!

(A)

30

(B)

38

(C)

42

(D)

44

Answer: (B)
Explanation:

Multiplication of 2×5 results into 10. So number of zeroes depend on the number of pairs of 2 and 5. In any factorial, number of 5’s is lesser than the number of 2’s. So, we need to count the maximum power of 5 in 155! [155/5] + [155/5²] + [155/5³] =31 + 6 +1 =38 Hence, number of zeroes is 38.

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