To carry out white box testing of a program, its flow chart representation is obtained as shown in the figure below:
For basis path based testing of this program, its cyclomatic complexity is
(A) 5
(B) 4
(C) 3
(D) 2
Answer: (C)
Explanation:
N(nodes) = 9
E(edges) = 10
Cyclomatic Complexity = E – N + 2P
= 10 -9 + 2*1
= 3
Quiz of this Question
Please comment below if you find anything wrong in the above post