What is the bit rate of a video terminal unit with 80 characters/line, 8 bits/character and horizontal sweep time of lOOµs (including 20 µs of retrace time)?
(A) 8 Mbps
(B) 6.4 Mbps
(C) 0.8 Mbps
(D) 0.64 Mbps
Answer: (B)
Explanation:
Total number of bits transmitted = 80 * 8 = 640 bits
Horizontal sweep time = 100 us
Bit rate = (640 * 106) / 100 = 6.4 Mbps
Thus, option (B) is correct.
Please comment below if you find anything wrong in the above post.
Quiz of this Question
GATE | GATE-IT-2004 | Question 11
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