What is the bit rate of a video terminal unit with 80 characters/line, 8 bits/character and horizontal sweep time of lOOµs (including 20 µs of retrace time)? (A) 8 Mbps (B) 6.4 Mbps (C) 0.8 Mbps (D) 0.64 Mbps Answer: (B) Explanation: Total number of bits transmitted = 80 * 8 = 640 bits Horizontal sweep time = 100 us Bit rate = (640 * 106) / 100 = 6.4 Mbps Thus, option (B) is correct. Please comment below if you find anything wrong in the above post. Quiz of this Question