If P, Q, R are Boolean variables, then (P + Q’)(PQ’ + PR)(P’R’ + Q’) simplifies
(A) PQ’
(B) PR’
(C) PQ’ + R
(D) PR” + Q
Answer: (A)
Explanation: Step by step explanation :
= (P + Q’)(PQ’ + PR)(P’R’ + Q’) = (PPQ’ + PPR + PQ’Q’ + PQ’R) (P’R’ + Q’) = (PQ’ + PR + PQ’ + PQ’R) (P’R’ + Q’) = (PP’Q’R’ + PP’R’R + PP’Q’R’ + PP’Q’RR’ + PQ’Q’ + PQ’R + PQ’Q’ + PQ’Q’R) = (0 + 0 + 0 + 0 + PQ’ + PQ’R + PQ’ + PQ’R) = PQ’ + PQ’R = PQ'(1 + R) = PQ’
So, option (A) is correct.