The Newton-Raphson iteration
can be used to compute the.
(A)
square root of R
(B)
logarithm of R
(C)
reciprocal of R
(D)
square of R
Answer: (A)
Explanation:
According to Newton-Raphson method,
xn+1 = xn − f(xn) / f′(xn)
So we try to bring given equation in above form. Given equation is :
xn+1 = xn/2 + R/(2xn) = xn − xn/2 + R/(2xn) = xn − (xn2 − R2)/(2xn)
So clearly f(x) = x2 − R, so root of f(x) means x2 − R = 0 i.e. we are trying to find square root of R. So option (C) is correct.
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