Write a program in C++ to print an Array using Recursion
1. Using Static Variable
Static variables have the property of preserving their value even after they are out of their scope! Hence, static variables preserve their previous value in their previous scope and are not initialized again in the new scope.
Syntax:
static data_type var_name = var_value;
C++
// C++ Program to print // an Array using Recursion #include <bits/stdc++.h> using namespace std;
// Recursive function to print the array void print_array( int arr[], int size)
{ // using the static variable
static int i;
// base case
if (i == size) {
i = 0;
cout << endl;
return ;
}
// print the ith element
cout << arr[i] << " " ;
i++;
// recursive call
print_array(arr, size);
} // Driver code int main()
{ int arr[] = { 3, 5, 6, 8, 1 };
int n = sizeof (arr) / sizeof (arr[0]);
print_array(arr, n);
return 0;
} |
Output:
3 5 6 8 1
2. Without using Static Variable
C++
// C++ Program to print // an Array using Recursion #include <bits/stdc++.h> using namespace std;
// Recursive function to print the array void print_array( int arr[], int size, int i)
{ // base case
if (i == size) {
cout << endl;
return ;
}
// print the ith element
cout << arr[i] << " " ;
i++;
// recursive call
print_array(arr, size, i);
} // Driver code int main()
{ int arr[] = { 3, 5, 6, 8, 1 };
int n = sizeof (arr) / sizeof (arr[0]);
print_array(arr, n, 0);
return 0;
} |
Output:
3 5 6 8 1
Time Complexity: O(n)
Auxiliary Space: O(1), If we consider recursive call stack then it would be O(n)
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