#include<iostream> using namespace std;
int x = 1;
void fun()
{ int x = 2;
{
int x = 3;
cout << ::x << endl;
}
} int main()
{ fun();
return 0;
} |
(A) 1
(B) 2
(C) 3
(D) 0
Answer: (A)
Explanation: The value of ::x is 1.
The scope resolution operator when used with a variable name, always refers to global variable.
Quiz of this Question