#include <stdio.h> int main() { int i; i = 1, 2, 3; printf("%d", i); return 0; }
(A) 1
(B) 3
(C) Garbage value
(D) Compile time error
Answer: (A)
Explanation: Comma acts as an operator. The assignment operator has higher precedence than comma operator. So, the expression is considered as (i = 1), 2, 3 and 1 gets assigned to variable i.
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