C
#include <stdio.h> #if X == 3 #define Y 3
#else #define Y 5
#endif int main()
{ printf (\"%d\", Y);
return 0;
} |
What is the output of the above program?
(A)
3
(B)
5
(C)
3 or 5 depending on value of X
(D)
Compile time error
Answer: (B)
Explanation:
In the first look, the output seems to be compile-time error because macro X has not been defined. In C, if a macro is not defined, the pre-processor assigns 0 to it by default. Hence, the control goes to the conditional else part and 5 is printed. See the next question for better understanding.
Quiz of this Question
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