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8085 program for hexadecimal counter

Write a program to count continuously in hexadecimal from FFH to 00H in a system with clock frequency 0.5 microseconds. Use register C to set up a delay of 1ms between each count and display output at one of the output ports. Problem Analysis:

  1. The hexadecimal counter is set by loading a register with starting number and decrementing it till zero is reached and then again decrementing it to will produce -1, which is two’s complement of FFH. Hence, the register again reaches FFH.
  2. The 1ms time delay is set up by the procedure shown in flowchart- The register is loaded with appropriate number such that the execution of above loop produces a time delay of 1ms.

Program:



Address Label Mnemonics
2000H   MVI B, FFH
2002H NEXT DCR B
2003H   MVI C, COUNT
2005H DELAY DCR C
2006H   JNZ DELAY
2009H   MOV A, B
200AH   OUTPORT#
200CH   JMP NEXT

The C register is the time delay register which is loaded by a value COUNT to produce a time delay of 1ms. To find the value of COUNT we do-

TD = TL + TO
where- TD = Time Delay
TL = Time delay inside loop
TO = Time delay outside loop

The delay loop includes two instructions- DCR C (4 T-states) and JNZ (10 T-states) So TL = 14*Clock period*COUNT => 14*(0.5*10-6)*COUNT => (7*10-6)*COUNT Delay outside the loop includes- DCR B : 4T MVI C, COUNT : 7T MOV A, B : 4T OUTPORT : 10T JMP : 10T Total : 35T TO= 35*Clock period => 17.5 microseconds So, 1ms= (17.5+ 7*COUNT)microsecond Therefore, COUNT=(140)10



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