8085 program for hexadecimal counter

Write a program to count continuously in hexadecimal from FFH to 00H in a system with clock frequency 0.5 microseconds. Use register C to set up a delay of 1ms between each count and display output at one of the output ports.

Problem Analysis:

  1. The hexadecimal counter is set by loading a register with starting number and decrementing it till zero is reached and then again decrementing it to will produce -1, which is two’s complement of FFH. Hence, the register again reaches FFH.
  2. The 1ms time delay is set up by the procedure shown in flowchart-
    time delay
    The register is loaded with appropriate number such that the execution of above loop produces a time delay of 1ms.

Program:



Address Label Mnemonics
2000H MVI B, FFH
2002H NEXT DCR B
2003H MVI C, COUNT
2005H DELAY DCR C
2006H JNZ DELAY
2009H MOV A, B
200AH OUTPORT#
200CH JMP NEXT

The C register is the time delay register which is loaded by a value COUNT to produce a time delay of 1ms.
To find the value of COUNT we do-

TD = TL + TO
where- TD = Time Delay
TL = Time delay inside loop
TO = Time delay outside loop

The delay loop includes two instructions- DCR C (4 T-states) and JNZ (10 T-states)
So TL = 14*Clock period*COUNT
=> 14*(0.5*10-6)*COUNT
=> (7*10-6)*COUNT

Delay outside the loop includes-
DCR B : 4T
MVI C, COUNT : 7T
MOV A, B : 4T
OUTPORT : 10T
JMP : 10T
Total : 35T

TO= 35*Clock period => 17.5 microseconds

So, 1ms= (17.5+ 7*COUNT)microsecond

Therefore, COUNT=(140)10



My Personal Notes arrow_drop_up

Student at Netaji Subhas Institute of Technology

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Improved By : Kartikaybhutani