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What are the odds of flipping 7 heads in a row?

A branch of mathematics that deals with the happening of a random event is termed probability. It is used in Maths to predict how likely events are to happen.

The probability of any event can only be between 0 and 1 and it can also be written in the form of a percentage.



The probability of event A is generally written as P(A).

Here P represents the possibility and A represents the event. It states how likely an event is about to happen. The probability of an event can exist only between 0 and 1 where 0 indicates that event is not going to happen i.e. Impossibility and 1 indicates that it is going to happen for sure i.e. Certainty



If we are not sure about the outcome of an event, we take help of the probabilities of certain outcomes—how likely they occur. For a proper understanding of probability we take an example as tossing a coin:

There will be two possible outcomes—heads or tails.

The probability of getting heads is half. You might already know that the probability is half/half or 50% as the event is an equally likely event and is complementary so the possibility of getting heads or tails is 50%.

Formula of Probability

Probability of an event, P(A) = Favorable outcomes / Total number of outcomes

Some Terms of Probability Theory

Some Probability Formulas

Addition rule: Union of two events, say A and B, then

P(A or B) = P(A) + P(B) – P(A∩B)

P(A ∪ B) = P(A) + P(B) – P(A∩B)

Complementary rule: If there are two possible events of an experiment so the probability of one event will be the Complement of another event. For example – if A and B are two possible events, then

P(B) = 1 – P(A) or P(A’) = 1 – P(A).

P(A) + P(A′) = 1.

Conditional rule: When the probability of an event is given and the second is required for which first is given, then

P(B, given A) = P(A and B), P(A, given B). It can be vice versa

P(B∣A) = P(A∩B)/P(A)

Multiplication rule: Intersection of two other events i.e. events A and B need to occur simultaneously. Then

P(A and B) = P(A)⋅P(B).

P(A∩B) = P(A)⋅P(B∣A)

What are the odds of flipping 7 heads in a row?

Solution:

Probability of an event = (number of favorable event) / (total number of event).

P(B) = (occurrence of Event B) / (total number of event).

Probability of getting one head = 1/2.

here Tossing a coin is an independent event, its not dependent on how many times it has been tossed.

Probability of getting 2 heads in a row = probability of getting head first time × probability of getting head second time.

Probability of getting 2 head in a row = (1/2) × (1/2)

Therefore, the probability of flipping 7 heads in a row = (1/2)7

Similar Questions

Question 1: What are the chances of flipping 8 heads in a row?

Solution:

Probability of an event = (number of favorable event) / (total number of event).

P(B) = (occurrence of Event B) / (total number of event).

Probability of getting one head = 1/2

here Tossing a coin is an independent event, its not dependent on how many times it has been tossed.

Probability of getting 3 heads in a row = probability of getting head first time × probability of getting head second time x probability of getting head third time

Probability of getting 3 head in a row = (1/2) × (1/2) × (1/2)

Therefore, the probability of getting 8 heads in a row = (1/2)8

Question 2: What are the chances of flipping 13 tails in a row?

Solution:

Probability of an event =  (number of favorable event) / (total number of event)

P(B) = (occurrence of Event B) / (total number of event)

Probability of getting one tail = 1/2

here if Tossing a coin is an independent event, its not dependent on how many times it has been tossed.

Probability of getting 3 tails in a row = probability of getting tail first time × probability of getting tail second time x probability of getting tail third time

Probability of getting 3 tails in a row = (1/2) × (1/2) × (1/2)

Therefore, the probability of getting 13 tails in a row = (1/2)13

Question 3: What is the probability of flipping a coin 14 times and getting 14 heads?

Solution:

15 times coin tosses. This means,

Total observations = 215 (According to binomial concept)

Required outcome → 20 Heads {H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,}

This can occur only ONCE!

hus, required outcome =1

Now put the probability formula  

Probability (14 Heads) = (1⁄2)14 = 1⁄32768

Hence, the probability that it will always land on the HEAD side will be, (1⁄2)14 = 1⁄16384

Question 4: What are the chances of flipping 25 heads in a row?

Solution:

Probability of an event = (number of favorable event) / (total number of event).

P(B) = (occurrence of Event B) / (total number of event)

Probability of getting one head = 1/2

here Tossing a coin is an independent event, its not dependent on how many times it has been tossed.

Probability of getting 3 heads in a row = probability of getting head first time × probability of getting head second time x probability of getting head third time

Probability of getting 3 head in a row = (1/2) × (1/2) × (1/2)

Therefore, the probability of getting 25 heads in a row = (1/2)25

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