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What is the probability of getting 3 heads on tossing a coin three times?

A branch of mathematics that deals with the happening of a random event is termed probability. It is used in Maths to predict how likely events are to happen.

The probability of any event can only be between 0 and 1 and it can also be written in the form of a percentage.



The probability of event A is generally written as P(A).

Here P represents the possibility and A represents the event. It states how likely an event is about to happen. The probability of an event can exist only between 0 and 1 where 0 indicates that event is not going to happen i.e. Impossibility and 1 indicates that it is going to happen for sure i.e. Certainty



If we are not sure about the outcome of an event, we take help of the probabilities of certain outcomes—how likely they occur. For a proper understanding of probability we take an example as tossing a coin:

There will be two possible outcomes—heads or tails.

The probability of getting heads is half. You might already know that the probability is half/half or 50% as the event is an equally likely event and is complementary so the possibility of getting heads or tails is 50%.

Formula of Probability

Probability of an event, P(A) = Favorable outcomes / Total number of outcomes

Some Terms of Probability Theory

Some Probability Formulas

Addition rule: Union of two events, say A and B, then

P(A or B) = P(A) + P(B) – P(A∩B)

P(A ∪ B) = P(A) + P(B) – P(A∩B)

Complementary rule: If there are two possible events of an experiment so the probability of one event will be the Complement of another event. For example – if A and B are two possible events, then

P(B) = 1 – P(A) or P(A’) = 1 – P(A).

P(A) + P(A′) = 1.

Conditional rule: When the probability of an event is given and the second is required for which first is given, then P(B, given A) = P(A and B), P(A, given B). It can be vice versa

P(B∣A) = P(A∩B)/P(A)

Multiplication rule: Intersection of two other events i.e. events A and B need to occur simultaneously. Then 

P(A and B) = P(A)⋅P(B).

P(A∩B) = P(A)⋅P(B∣A)

What is the probability of getting 3 heads on tossing a coin three times?

Solution:

For this first we need to consider all the possible outcomes if we flip a coin 3 times.

Outcomes will be {THH, HTH, HHT, TTH, THT, HTT, TTT, HHH }

Total number of outcome = 8

So the favourable outcome of having three heads = HHH

                                                                              = 1

Therefore the probability of getting at least three heads = Probability of an event = Favorable outcomes / Total number of outcomes

P(A) = Favorable outcomes / Total number of outcomes

= 1/8

Similar Questions

Question 1: What is the probability of flipping one coin?

Solution:

To calculate the probability of the event, It contains only one element and sample space contains two elements, so the sample space will be {H, T}

So, total number of outcome is 2.

What is the probability of a coin landing on tails or head?

The probability of landing on head  is given as: P(A) = Favorable outcomes / Total number of outcomes

= 1/2

Same for the probability of landing on tail, P(A) = Favorable outcomes / Total number of outcomes

= 1/2    

Question 2: What are the chances of flipping 20 tails in a row?

Solution:

Probability of an event = (number of favorable event) / (total number of event).

P(B) = (occurrence of Event B) / (total number of event).

Probability of getting one tail = 1/2.

Here, tossing a coin is an independent event, its not dependent on how many times it has been tossed.

Probability of getting 3 tails in a row = probability of getting tail first time × probability of getting tail second time × probability of getting tail third time

Probability of getting 3 tails in a row = (1/2) × (1/2) × (1/2)

Therefore, the probability of getting 20 tails in a row = (1/2)20

Question 3: What is the probability of flipping a coin 20 times and getting 20 tails?

Solution:

20 times coin tosses. This means,

Total observations = 220 (According to binomial concept)

Required outcome → 20 tails {H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,H,}

This can occur only ONCE!

Thus, required outcome =1

Now put the probability formula  

Probability (20 Tails) = (1⁄2)20 = 1⁄1048576

Hence, the probability that it will always land on the TAIL side will be, (1⁄2)20 = 1⁄1048576

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