Consider a 32 – bit microprocessor, with a 16 – bit external data bus, driven by an 8 MHz input clock. Assume that this microprocessor has a bus cycle whose minimum duration equals four input clock cycles. What is the maximum data transfer rate for this microprocessor?
(A)
8 x 106 bytes/sec
(B)
4 x 106 bytes/sec
(C)
16 x 106 bytes/sec
(D)
4 x 109 bytes/sec
Answer: (B)
Explanation:
In a 32 – bit microprocessor, with a 16 – bit external data bus, data transferred per bus cycle = 2B.
Bus clock = 8 MHz.
Minimum bus cycle duration = 4 clock cycles
Maximum bus cycle rate = 8 MHz / 4 = 2 M/sec
Data transfer rate = bus cycle rate * data per bus cycle = 2 M * 2 = 4 * 106 B/sec.
So, option (B) is correct.
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