UGC-NET | UGC NET CS 2015 Dec – II | Question 28

Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk?
(A) 57 sec
(B) 49 sec
(C) 48 sec
(D) 17 sec

Answer: (B)
Explanation: Transfer time(TT) = ((1024 bytes * 16 ms) / (16384 bytes )) = 1 msec
Rotational latency = 16 msec / 2 = 8 msec
seek time = 40 msec.
total time = seek time + rotational latency + transfer time
= 40 + 8 + 1 = 49 msec
So, option (B) is correct.
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