Given time in hours, find the time in minutes at which the minute hand and hour hand coincide in the next one hour.
Examples:
Input : 3 Output : (180/11) minutes
Input :7 Output : (420/11) minutes
Approach :
1. Take two variables for hour “h1 and h2” and then find the angle “theta” [theta = (30 * h1)] and then divide it by “11” to find the time in minute(m). We are dividing with 11, because the hands of a clock coincide 11s time in 12 hours and 22 times in 24 hours :
Formula : This can be calculated using the formula for time h1 to h2 means [11m / 2 – 30 (h1)]
this implies [ m = ((30 * h1) * 2) / 11 ] ]
[ m = (theta * 2) / 11 ]
where [theta = (30 * h1) ] where A and B are hours i.e if given hour is (2, 3) then A = 2 and B = 3 .
// CPP code to find the minute at which // the minute hand and hour hand coincide #include <bits/stdc++.h> using namespace std;
// function to find the minute void find_time( int h1)
{ // finding the angle between minute
// hand and the first hour hand
int theta = 30 * h1;
cout << "(" << (theta * 2) << "/"
<< "11"
<< ")"
<< " minutes" ;
} // Driver code int main() {
int h1 = 3;
find_time(h1);
return 0;
} |
// Java code to find the minute // at which the minute hand and // hour hand coincide import java.io.*;
class GFG
{ // function to find the minute
static void find_time( int h1)
{
// finding the angle between
// minute hand and the first
// hour hand
int theta = 30 * h1;
System.out.println( "(" + theta *
2 + "/" +
" 11 ) minutes" );
}
//Driver Code
public static void main (String[] args)
{
int h1 = 3 ;
find_time(h1);
}
} // This code is contributed by // upendra singh bartwal |
# Python3 code to find the # minute at which the minute # hand and hour hand coincide # Function to find the minute def find_time(h1):
# Finding the angle between
# minute hand and the first
# hour hand
theta = 30 * h1
print ( "(" , end = "")
print ((theta * 2 ), "/ 11) minutes" )
# Driver code h1 = 3
find_time(h1) # This code is contributed by # Smitha Dinesh Semwal |
// C# code to find the minute // at which the minute hand // and hour hand coincide using System;
class GFG
{ // function to find the minute
static void find_time( int h1)
{
// finding the angle between minute
// hand and the first hour hand
int theta = 30 * h1;
Console.WriteLine( "(" + theta * 2 +
"/" + " 11 )minutes" );
}
//Driver Code
public static void Main()
{
int h1 = 3;
find_time(h1);
}
} // This code is contributed by vt_m. |
<?php // PHP code to find the minute // at which the minute hand and // hour hand coincide // function to find the minute function find_time( $h1 )
{ // finding the angle between
// minute hand and the first
// hour hand
$theta = 30 * $h1 ;
echo ( "(" . ( $theta * 2) .
"/" . "11" . ")" .
" minutes" );
} // Driver code $h1 = 3;
find_time( $h1 );
// This code is contributed by Ajit. ?> |
<script> // JavaScript code to find the minute at which // the minute hand and hour hand coincide // function to find the minute function find_time(h1)
{ // finding the angle between minute // hand and the first hour hand theta = 30 * h1; document.write( "(" + (theta * 2) + "/"
+ "11"
+ ")"
+ " minutes" );
} // Driver code h1 = 3; find_time(h1); // This code is contributed by Surbhi Tyagi. </script> |
(180/11) minutes
Time Complexity: O(1)
Auxiliary Space: O(1)