Open In App

Rolling Friction

Rolling Friction is a frictional force that opposes rolling objects. Rolling friction is applicable where the body moves along its curved surfaces. For example, wheels in vehicles, ball bearings, etc. are examples of rolling friction.

In this article, we will learn about rolling friction, its definition, laws, formulas, causes, coefficient, and the factors that affect it. We will also learn how rolling friction is different from sliding friction.



What is Rolling Friction?

Rolling friction is a type of friction, that opposes the motion of rolling objects. For example, if a ball is rolling on the floor, eventually it will stop. This happens because the ball is going to experience resistance in the direction of its motion. The frictional force acts on the ball, which is opposite to the motion of the ball and slows down the ball. The deformation of surfaces is the reason for rolling friction. Rolling friction is valid in the case for ball bearings-car tires, bowling balls, etc.



Rolling Friction Examples

Here are some examples of rolling friction

Laws of Rolling Friction

There are three laws of rolling friction:

Law 1: As the rolling friction becomes smoother, the weight acting on the wheels tends to decrease.

Law 2: Friction expressed as the product of load and constant where constant is raised to a fractional power.

F = kLn

where F is Rolling Friction, K is frictional constant, L is load, n is fractional power.

Law 3: Load is directly proportional to rolling friction force, and the degree of curve is inversely proportional to the rolling friction force.

F = 𝝻 ×W/r

Here, F = force of rolling friction

Rolling Friction Formula

Consider the following figure:

There are two formulas of rolling friction which are derived from the laws of rolling friction. The first formula related to rolling friction is given as:

F = KLn

Here,

The second formula of rolling friction is given as

F = 𝝻 ×W/r

Here, F = force of rolling friction

Cause of Rolling Friction

Rolling friction arises from several factors related to the interaction between a rolling object and the surface over which it rolls. The main causes of rolling friction include:

Deformation of Surfaces: When a wheel or a cylindrical object rolls over a surface, both the object and the surface undergo deformation. The surface deforms slightly under the pressure of the rolling object causing rolling friction to the wheel.

Elastic Hysteresis: Elastic hysteresis is the loss of energy that occurs when an elastic material, such as rubber, undergoes deformation and then returns to its original shape. As the tire or wheel rolls over the surface, it undergoes repeated cycles of compression and expansion, causing energy to be dissipated as heat. This also causes rolling friction.

Internal Friction: Internal friction within the material of the rolling object, such as the rubber in tires, also contributes to rolling resistance. As the tire rolls, internal friction within the tire material generates heat and dissipates energy, increasing the resistance.

Surface Irregularities: Surface irregularities, such as roughness, bumps, and imperfections, on both the rolling object and the surface over which it rolls can increase rolling friction.

Adhesion and Cohesion: Adhesion and cohesion between the rolling object and the surface can also contribute to rolling friction. Molecular interactions between the materials of the rolling object and the surface can create adhesion and cohesion forces, which resist the motion of the rolling object and increase rolling resistance.

Coefficient of Rolling Friction

The coefficient of rolling friction is the ratio of the rolling friction to whole weight of object. The coefficient of rolling friction when given may be formulated mathematically as

F= μ × W

Factors Affecting Rolling Friction

The following factors affect rolling friction:

Difference Between Rolling And Sliding Friction

The differences between rolling friction and sliding friction have been listed in the table below:

Rolling friction

Sliding friction

The use of a rolling motion allows for the avoidance of the use of the friction.

Frictional sliding arises when the surfaces are dragged against each other or not.

Rolling Friction occurs due to deformation of rolling objects.

Sliding friction occurs due to interlocking of microscopic surfaces

The value of the coefficient of rolling friction is determined by the radius of rolling body, as well as how much it depress, and the hardness of the surface.

The value of sliding friction coefficient depends on the real surface roughness and might be affected by the temperature to some degree.

Coefficient of rolling friction: Fr = μrN

Coefficient of sliding friction: Fk = μkN

Advantages and Disadvantages of Rolling Friction

We know that Friction is a necessary evil. Hence, rolling friction has both advantages and disadvantages. The advantages and disadvantages of rolling friction is tabulated below:

Advantages of Rolling Friction

Disadvantages of Rolling Friction

It allows for efficient energy transfer between a rolling object and the surface over which it rolls

It requires energy to overcome, particularly in scenarios where heavy loads or high speeds are involved

It reduces wear and tear on both the rolling object and the surface.

Minimizing rolling friction requires complex design

It enables ease of movement for objects such as vehicles, luggage, and machinery.

In some situations, such as when braking or cornering at high speeds, rolling friction may not provide sufficient grip

It improves efficiency in many mechanical systems and devices

It may not perform well in certain conditions, such as on rough or uneven surfaces, at high temperatures, or in extreme environments.

It produces less noise and vibration compared to sliding friction

It can still contribute to noise pollution and vibration levels, particularly in heavy-duty machinery and transportation systems

Related Articles

Types of Friction

Rolling Motion

Increasing and Reducing Friction

Laws of Friction

Fluid Friction

Friction: A Necessary Evil 

Numericals on Rolling Friction

Example 1: Considering a static friction, a 100 kg crate push across a horizontal floor is at a constant speed. A coefficient of rolling friction per one the crate and floor unit is 0.02.(157 words) What is the force needed for pushing the truck?

Solution:

Here, μ = 0.02

Fr = μN

The normal force can be calculated as:

N = mg

N = 100 × 9.81

N = 981

Fr = 0.02 × 981

Fr = 19.62N

Example 2: The bike covers twenty meters on the down-slope at a continuous pace of twenty meters per second. The coefficient of rolling resistance of the bicycle tires and the road have 0.01 as the value. What is the magnitude of rolling friction (rostructural material) that acts on the bicycle?

Solution:

Here, μ = 0.01

The normal force is equal to the weight of the bicycle and the rider, which we will assume is 100 kg.

N = mg

N = 100 × 9.81

N = 981

Fr = 0.01 × 981

Fr = 9.81 N

Example 3: A box with 200 kg weight is moving straight out on the floor with the ground speed. The rolling resistance between the crate and the floor is equal to 0.03. Let’s see: what is the acceleration?

Solution:

N = mg = 200 × 9.81 = 1962 N

Fr = μ × N = 0.03 × 1962 = 58.86 N

Example 4: A rolling ball having a mass of 5 kg rides on the surface, under a rolling resistance coefficient of 0.02. Analyze the rolling friction force.

Solution:

Given:

Ball weight (W): 5 kg

Coefficient of rolling friction (μ): 0.02

N = W × g = 5 × 9.81 = 49.05 N

Fr = μ × N = 0.02 × 49.05 = 0.981 N

Example 5: Derive the rolling friction force for a rolling object with radius of curvature = 0.5 meters and at 50 kg load by making use of the relevant formula.

Solution:

Given:

Radius of curvature (r): 0.5 meters

Load (W): 50 kg

Fr = μ × W × r

N = W × g = 50 × 9.81 = 490.5N

Fr = μ × W × r = μ × 490.5 × 0.5 = 245.25μ

Example 6: A bicycle wheels along the road 30 meters in distance with a coefficient of the rolling resistance of 0.015. If the total weight of the bicycle and rider amounts to 150kg, what is the maximum value of rolling friction?

Solution:

N = mg = 150 × 9.81 = 1471.5 N

Fr = μ × N = 0.015 × 1471.5 = 22.0725 N

Rolling Friction Practice Problems

1. Considering a static friction, a 1000 kg crate push across a horizontal floor is at a constant speed. A coefficient of rolling friction per one the crate and floor unit is 0.06. What is the force needed for pushing the truck?

2. The bike covers twenty meters on the down-slope at a continuous pace of twenty meters per second. The coefficient of rolling resistance of the bicycle tires and the road have 0.09 as the value. What is the magnitude of rolling friction (restructure material) that acts on the bicycle?

3. A box with 2900 kg weight is moving straight out on the floor with the ground speed. The rolling resistance between the crate and the floor is equal to 0.09. what is the acceleration?

4. Derive the rolling friction force for a rolling object with radius of curvature = 60 meters and at 5000 kg load by making use of the relevant formula.

5. Derive the rolling friction force for a rolling object with radius of curvature = 0.8 meters and at 5 kg load by making use of the relevant formula.

Rolling Friction Frequently Asked Questions

What is Friction?

A force that oppose the motion of the object is fictional force.

What is Kinetic friction?

Kinetic friction is the friction that happens in between moving surfaces

What is Static friction?

Friction acting between two surfaces that are not moving is static friction.

What is meant by rolling friction?

Rolling Friction is a frictional force that opposes rolling objects.

What is the example for rolling friction?

Football rolling on the ground will slow down as time proceeds from the mechanisms of rolling friction.

What are the ways to reduce Rolling Friction?

produce surface which are smooth or lubricants like grease or oil will reduce rolling friction.


Article Tags :