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Python | sympy.nP() method

With the help of sympy.nP() method, we can calculate the number of permutation of a given length in SymPy.

Syntax: nP(items, k)



Parameter:
items – An integer, a list or a string upon which permutation is to be calculated.
k – An integer specifying the length of the permutation.

Returns: Returns the number of permutation of a given length.



Example #1:




# import sympy 
from sympy import * 
  
items = "abca"
k = 3
print("Value of k = {} and the items are = {}".format(k, items))
   
# Use sympy.nP() method 
permutations = nP(items, k)  
      
print("Permutation : {}".format(permutations))  

Output:

Value of k = 3 and the items are = abca
Permutation : 12

Example #2:




# import sympy 
from sympy import * 
  
items = [2, 1, 3, 5, 4]
k = 3
print("Value of k = {} and the items are = {}".format(k, items))
   
# Use sympy.nP() method 
permutations = nP(items, k)  
      
print("Permutation : {}".format(permutations))  

Output:

Value of k = 3 and the items are = [2, 1, 3, 5, 4]
Permutation : 60
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