# Python | sympy.nP() method

With the help of sympy.nP() method, we can calculate the number of permutation of a given length in SymPy.

Syntax: nP(items, k)

Parameter:
items – An integer, a list or a string upon which permutation is to be calculated.
k – An integer specifying the length of the permutation.

Returns: Returns the number of permutation of a given length.

Example #1:

 `# import sympy  ` `from` `sympy ``import` `*`  ` `  `items ``=` `"abca"` `k ``=` `3` `print``(``"Value of k = {} and the items are = {}"``.``format``(k, items)) ` `  `  `# Use sympy.nP() method  ` `permutations ``=` `nP(items, k)   ` `     `  `print``(``"Permutation : {}"``.``format``(permutations))   `

Output:

```Value of k = 3 and the items are = abca
Permutation : 12
```

Example #2:

 `# import sympy  ` `from` `sympy ``import` `*`  ` `  `items ``=` `[``2``, ``1``, ``3``, ``5``, ``4``] ` `k ``=` `3` `print``(``"Value of k = {} and the items are = {}"``.``format``(k, items)) ` `  `  `# Use sympy.nP() method  ` `permutations ``=` `nP(items, k)   ` `     `  `print``(``"Permutation : {}"``.``format``(permutations))   `

Output:

```Value of k = 3 and the items are = [2, 1, 3, 5, 4]
Permutation : 60
```

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