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jQuery UI dialog close() Method
close() method is used to disable the dialog. This method does not accept any argumentSyntax:$( ".selector" ).dialog("close");Approach: First, add jQuery UI scripts needed...
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Web Technologies
HTML
JQuery
jQuery-UI
jQuery UI dialog isOpen() Method
isOpen() Method is used to check if the dialog box is open. This method does not accept any argumentSyntax:$( ".selector" ).dialog("isOpen");Approach: First, add jQuery UI...
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Web Technologies
HTML
JQuery
jQuery-UI
jQuery UI Dialog autoOpen Option
AutoOpen option indicates if the dialog box should be automatically open when the page is initially loaded or not. By default, value is true.Syntax:$( ".selector" ).dialog...
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Web Technologies
HTML
JQuery
jQuery-UI
Class 11 RD Sharma Solutions - Chapter 23 The Straight Lines - Exercise 23.9
Question 1: Reduce the equation √3x + y + 2 = 0 to:(i) slope-intercept form and find slope and y-intercept(ii) Intercept form and find intercept on the axes(iii) The norma...
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Mathematics
School Learning
Class 11
RD Sharma Solutions
RD Sharma Class-11
Class 8 RD Sharma Solutions - Chapter 18 Practical Geometry - Exercise 18.5
Question 1: Construct a quadrilateral ABCD given that AB = 4 cm, BC = 3 cm, ∠A = 75°, ∠B = 80° and ∠C = 120°?Solution:We have, AB = 4 cm, BC = 3 cm, ∠A = 75°, ∠B = 80° and...
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Mathematics
School Learning
Class 8
RD Sharma Solutions
RD Sharma Class-8
Class 12 RD Sharma Solutions- Chapter 19 Indefinite Integrals - Exercise 19.7
Integrate the following integrals:Question 1. ∫sin4x cos7x dxSolution:Let I=[Tex]\int \sin4x\cos7x\,dx[/Tex]We know,[Tex]2\sin A \cos B= \sin(A+B)+\sin(A-B)[/Tex]Applying ...
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Picked
Mathematics
School Learning
Class 12
RD Sharma Solutions
RD Sharma Class-12
Class 8 RD Sharma Solutions - Chapter 18 Practical Geometry - Exercise 18.3
Question 1: Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ∠B = 80°?Solution:The given details are AB = 3.8 cm, BC = 3.4 cm, ...
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Mathematics
School Learning
Class 8
RD Sharma Solutions
RD Sharma Class-8
Class 8 RD Sharma Solutions - Chapter 18 Practical Geometry - Exercise 18.2
Question 1: Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 3.8 cm?Solution:We have, AB = 3.8 cm, BC = 3.0 cm, AD = 2.3...
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Picked
Mathematics
School Learning
Class 8
RD Sharma Solutions
RD Sharma Class-8
Class 8 RD Sharma Solutions- Chapter 18 Practical Geometry - Exercise 18.1
Question 1: Construct a quadrilateral ABCD in which AB = 4.4 cm, BC = 4 cm, CD = 6.4 cm, DA = 3.8 cm and BD = 6.6 cm?Solution:Given: AB = 4.4 cm, BC = 4 cm, CD = 6.4 cm, D...
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Mathematics
School Learning
Class 8
RD Sharma Solutions
RD Sharma Class-8
Google Cloud Platform - Building CI/CD Pipeline For Package Delivery
Problem Statement:When TCS was just a prototype, bundling up their app and sharing it with the testing team was fairly simple. The coders could just email a link to the ap...
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Computer Subject
Google-Cloud-Platform
Google Cloud Platform - Concept of Nodes in Kubernetes
In this article, we will figure out how Kubernetes actually runs containers on nodes. Let's go over the concepts that make Kubernetes usable, scalable, and just downright ...
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Computer Subject
Google-Cloud-Platform
Google Cloud Run - Working with Python
Python is one of the most popular programming languages and growing. It's well-suited for a number of use cases, including web applications, machine learning, and big data...
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Computer Subject
Google-Cloud-Platform
Class 10 NCERT Solutions- Chapter 9 Some Application of Trigonometry - Exercise 9.1 | Set 2
Content of this article is merged in the article: Chapter 9 Some Application of Trigonometry - Exercise 9.1Question 11. A TV tower stands vertically on the bank of a canal...
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Mathematics
School Learning
NCERT
Class 10
NCERT Solutions Class-10
Google Cloud Platform - Overview of Data Migration Service
In this article, we will explore the Google cloud platform's Database Migration Service or DMS. We are also going to walk through a quick, simple migration to Cloud SQL us...
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Computer Subject
Google-Cloud-Platform
Class 12 RD Sharma Solutions- Chapter 21 Areas of Bounded Regions - Exercise 21.4
Question 1. Find the area of the region between the parabola x = 4y − y2 and the line x = 2y − 3.Solution:Area of the bounded region[Tex]=\int_{-1}^{3}(4y-y^2-2y+3)dy\\ =[...
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Picked
Mathematics
School Learning
Class 12
RD Sharma Solutions
RD Sharma Class-12
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