-
Type
Suppose f(x) = 0 = g(x) as x→ a or as x→ 0 This form can be solved directly by the application of L’ Hospital rule. Provided that both f’(x) and g’(x) exist at x = a and g’(x) ≠ 0. -
Type
Suppose f(x) = ∞ = g(x) as x→ a or as x→ ±∞. This form can be solved by first converting it to the type as- Now we can apply L’ Hospital rule as usual to solve it. It is advised to convert to 0/0 form as the differentiation of numerator and denominator may never terminate in some problems. -
Type
Suppose f(x) = 0 and g(x) = ∞ as x→ a or as x→ ±∞ then the product f(a).g(a) is undefined. We need to solve it by converting it to the type 0/0 or ∞/∞. or Now we need to apply L’ Hospital rule. -
Type
Suppose f(x) = ∞ = g(x) as x→ a. this type is solved by again converting to the 0/0 form by following method : As we achieve 0/0 form, now we can apply L’ Hospital rule. -
Type
To evaluate these forms consider: Taking logarithm both sides Taking the limit as x→ a or x→ ±∞ Then
Article Tags :
Recommended Articles