(A) -1
(B) 1
(C) 0
(D) π
Answer: (B)
Explanation:
In the above integral
f(x) = (x- π)^3 (sinx)
f(2π – x) = (2π – x – π)^3 (sinx)
= (π – x )^3 (sinx)
= -( x – π )^3 (sinx)
=-f(x)
so , ∫ (x- π)^3 (sinx) dx =1
since ,
∫f(x)dx= 1
whenever f(2π – x) = -f(x)
hence option B is correct