A serial transmission Ti uses 8 information bits, 2 start bits, 1 stop bit and 1 parity bit for each character. A synchronous transmission T2 uses 3 eight bit sync characters followed by 30 eight bit information characters. If the bit rate is 1200 bits/second in both cases, what are the transfer rates of Ti and T2?
(A)
100 characters/sec, 153 characters/sec
(B)
80 characters/sec, 136 characters/sec
(C)
100 characters/sec, 136 characters/sec
(D)
80 characters/sec, 153 characters/sec
Answer: (C)
Explanation:
Transfer Rate = Bit rate * ( Information bits / Total number of bits transmitted)
Serial communication :
Total number of bits transmitted = 8 + 2 + 1 + 1 = 12 bits
Information bits = 8 bits
Transfer Rate = 1200 * (8/12) = 800 bits/sec
Given size of one character is 8 bits.
So, Transfer Rate = 800/8 = 100 characters/sec
Synchronous transmission :
Total number of bits transmitted = 3 + 30 = 33 bits
Information bits = 30 bits
Transfer Rate = 1200 * (30/33) = 1090.90 bits/sec
Given size of one character is 8 bits.
So, Transfer Rate = 1090.90/8 ≈ 136 characters/sec.
Thus, option (C) is correct.
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