Let S denote the set of all functions f: {0,1}4 -> {0,1}. Denote by N the number of functions from S to the set {0,1}. The value of Log2Log2N is ______.
(A) 12
(B) 13
(C) 15
(D) 16
Answer: (D)
Explanation:
The given mapping S is defined by f:{0,1}^4 -> {0,1} . So, number of functions from S will be 2^16. Now N is defined by f : S-> {0,1}. So Number of functions from S to {0,1} will be 2^S. Hence log2log2N = log2S = 16