Find the center of the circle using endpoints of diameter

Given two endpoint of diameter of a circle (x1, y1) and (x2, y2) find out the center of a circle. 
Examples :

Input  : x1 = -9, y1 = 3, and 
         x2 = 5, y2 = –7
Output : -2, –2

Input  :  x1 = 5, y1 = 3 and 
          x2 = –10 y2 = 4
Output : –2.5, 3.5

Midpoint Formula: 
The midpoint of two points, (x1, y2) and (x2, y2) is : M = ((x ₁ + x ₂) / 2, (y ₁ + y ₂) / 2)
The center of the circle is the mid point of its diameter so we calculate the mid point of its diameter by using midpoint formula. 

C++

// C++ program to find the
// center of the circle
#include <iostream>
using namespace std;

// function to find the
// center of the circle
void center(int x1, int x2,
            int y1, int y2)
{

    cout << (float)(x1 + x2) / 2 <<
          ", " << (float)(y1 + y2) / 2;
}

// Driven Program
int main()
{
    int x1 = -9, y1 = 3, x2 = 5, y2 = -7;
    center(x1, x2, y1, y2);
    return 0;
}

Java

// Java program to find the
// center of the circle
class GFG {

    // function to find the
    // center of the circle
    static void center(int x1, int x2,
                            int y1, int y2)
    {

        System.out.print((float)(x1 + x2) / 2
            + ", " + (float)(y1 + y2) / 2);
    }

    // Driver Program to test above function
    public static void main(String arg[]) {

        int x1 = -9, y1 = 3, x2 = 5, y2 = -7;
        center(x1, x2, y1, y2);
    }
}

// This code is contributed by Anant Agarwal.

Python3

# Python3 program to find
# the center of the circle

# Function to find the
# center of the circle
def center(x1, x2, y1, y2) :

    print(int((x1 + x2) / 2), end= "")
    print(",", int((y1 + y2) / 2) )

# Driver Code
x1 = -9; y1 = 3; x2 = 5; y2 = -7
center(x1, x2, y1, y2)

# This code is contributed by Smitha Dinesh Semwal

C#

// C# program to find the
// center of the circle
using System;

class GFG {

    // function to find the
    // center of the circle
    static void center(int x1, int x2,
                            int y1, int y2)
    {

        Console.WriteLine((float)(x1 + x2) / 2
                + ", " + (float)(y1 + y2) / 2);
    }

    // Driver Program to test above function
    public static void Main() {

        int x1 = -9, y1 = 3, x2 = 5, y2 = -7;
        center(x1, x2, y1, y2);
    }
}

// This code is contributed by vt_m.

PHP

<?php
// PHP program to find the
// center of the circle

// function to find the
// center of the circle
function center($x1, $x2, $y1, $y2)
{

    echo((float)($x1 + $x2) / 2 . ", " .
                (float)($y1 + $y2) / 2);
}

// Driven Code
$x1 = -9; $y1 = 3; $x2 = 5; $y2 = -7;
center($x1, $x2, $y1, $y2);

// This code is contributed by Ajit.
?>

Javascript

<script>

// javascript program to find the
// center of the circle

// function to find the
    // center of the circle
    function center(x1, x2,
                     y1, y2)
    {

        document.write((x1 + x2) / 2
            + ", " + (y1 + y2) / 2);
    }

// Driver Function

         let x1 = -9, y1 = 3, x2 = 5, y2 = -7;
        center(x1, x2, y1, y2);

    // This code is contributed by susmitakundugoaldanga.
</script>

Output :

-2, -2

Time complexity: O(1)
Auxiliary Space: O(1)