Prerequisite:
In this article, we will see some designing of Non-Deterministic Finite Automata (NFA).
Problem-1:
Construction of a minimal NFA accepting a set of strings over {a, b} in which each string of the language starts with ‘a’.
Explanation:
The desired language will be like:
L1 = {ab, abba, abaa, ...........}
Here as we can see that each string of the above language starts with ‘a’ and end with any alphabet either ‘a’ or ‘b’. But the below language is not accepted by this NFA because none of the string of below language starts with ‘a’.
L2 = {ba, ba, babaaa..............}
The state transition diagram of the desired language will be like below:
In the above NFA, the initial state ‘X’ on getting ‘a’ as the input it transits to a final state ‘Y’. The final state ‘Y’ on getting either ‘a’ or ‘b’ as the input it remains in the state of itself.
Python Implementation:
#include <iostream> #include <string> void stateX( const std::string& n);
void stateY( const std::string& n);
void stateX( const std::string& n) {
// if length of n becomes 0
// then print not accepted
if (n.empty()) {
std::cout << "String not accepted" << std::endl;
} else {
// if at zero index
// 'a' found call
// stateY function
if (n[0] == 'a' ) {
stateY(n.substr(1));
}
// if at zero index
// 'b' then print
// not accepted
else if (n[0] == 'b' ) {
std::cout << "String not accepted" << std::endl;
}
}
} void stateY( const std::string& n) {
// if length of n becomes 0
// then print accepted
if (n.empty()) {
std::cout << "String accepted" << std::endl;
} else {
// if at zero index
// 'a' found call
// stateY function
if (n[0] == 'a' ) {
stateY(n.substr(1));
}
// if at zero index
// 'b' found call
// stateY function
else if (n[0] == 'b' ) {
stateY(n.substr(1));
}
}
} int main() {
// take input
std::string inputString= "ababa" ;
// call stateX function
// to check the input
stateX(inputString);
return 0;
} //This code is contributed by utkarsh |
public class StateMachine {
public static void stateX(String n) {
// if length of n becomes 0
// then print not accepted
if (n.isEmpty()) {
System.out.println( "String not accepted" );
} else {
// if at zero index
// 'a' found call
// stateY function
if (n.charAt( 0 ) == 'a' ) {
stateY(n.substring( 1 ));
}
// if at zero index
// 'b' then print
// not accepted
else if (n.charAt( 0 ) == 'b' ) {
System.out.println( "String not accepted" );
}
}
}
public static void stateY(String n) {
// if length of n becomes 0
// then print accepted
if (n.isEmpty()) {
System.out.println( "String accepted" );
} else {
// if at zero index
// 'a' found call
// stateY function
if (n.charAt( 0 ) == 'a' ) {
stateY(n.substring( 1 ));
}
// if at zero index
// 'b' found call
// stateY function
else if (n.charAt( 0 ) == 'b' ) {
stateY(n.substring( 1 ));
}
}
}
public static void main(String[] args) {
// take input
String inputString = "ababa" ;
// call stateX function
// to check the input
stateX(inputString);
}
} |
def stateX(n):
#if length of n become 0
#then print not accepted
if ( len (n) = = 0 ):
print ("string not accepted")
else :
#if at zero index
#'a' found call
#stateY function
if (n[ 0 ] = = 'a' ):
stateY(n[ 1 :])
#if at zero index
#'b' then print
#not accepted
elif (n[ 0 ] = = 'b' ):
print ("string not accepted")
def stateY(n):
#if length of n become 0
#then print accepted
if ( len (n) = = 0 ):
print ("string accepted")
else :
#if at zero index
#'a' found call
#stateY function
if (n[ 0 ] = = 'a' ):
stateY(n[ 1 :])
#if at zero index
#'b' found call
#stateY function
elif (n[ 0 ] = = 'b' ):
stateY(n[ 1 :])
#take input n = input ()
#call stateA function #to check the input stateX(n) |
using System;
class StateMachine
{ static void StateX( string n)
{
// if length of n becomes 0
// then print not accepted
if ( string .IsNullOrEmpty(n))
{
Console.WriteLine( "String not accepted" );
}
else
{
// if at zero index
// 'a' found call
// StateY function
if (n[0] == 'a' )
{
StateY(n.Substring(1));
}
// if at zero index
// 'b' then print
// not accepted
else if (n[0] == 'b' )
{
Console.WriteLine( "String not accepted" );
}
}
}
static void StateY( string n)
{
// if length of n becomes 0
// then print accepted
if ( string .IsNullOrEmpty(n))
{
Console.WriteLine( "String accepted" );
}
else
{
// if at zero index
// 'a' found call
// StateY function
if (n[0] == 'a' )
{
StateY(n.Substring(1));
}
// if at zero index
// 'b' found call
// StateY function
else if (n[0] == 'b' )
{
StateY(n.Substring(1));
}
}
}
static void Main()
{
// take input
string inputString = "ababa" ;
// call StateX function
// to check the input
StateX(inputString);
}
} |
output:
String accepted
Problem-2:
Construction of a minimal NFA accepting a set of strings over {a, b} in which each string of the language is not starting with ‘a’.
Explanation:
The desired language will be like:
L1 = {ba, bba, bbaa, ...........}
Here as we can see that each string of the above language is not starting with ‘a’ but can end with either ‘a’ or ‘b’. But the below language is not accepted by this NFA because some of the string of below language starts with ‘a’.
L2 = {ab, aba, ababaab..............}
The state transition diagram of the desired language will be like below:
In the above NFA, the initial state ‘X’ on getting ‘b’ as the input it transits to a final state ‘Y’. The final state ‘Y’ on getting either ‘a’ or ‘b’ as the input it remains in the state of itself.
Python Implementation:
def stateX(n):
#if length of n become 0
#then print not accepted
if ( len (n) = = 0 ):
print ("string not accepted")
else :
#if at zero index
#'b' found call
#stateY function
if (n[ 0 ] = = 'b' ):
stateY(n[ 1 :])
#if at zero index
#'a' then print
#not accepted
elif (n[ 0 ] = = 'a' ):
print ("string not accepted")
def stateY(n):
#if length of n become 0
#then print accepted
if ( len (n) = = 0 ):
print ("string accepted")
else :
#if at zero index
#'a' found call
#stateY function
if (n[ 0 ] = = 'a' ):
stateY(n[ 1 :])
#if at zero index
#'b' found call
#stateY function
elif (n[ 0 ] = = 'b' ):
stateY(n[ 1 :])
#take input n = input ()
#call stateA function #to check the input stateX(n) |