The d3.timeSaturdays() function in D3.js is used to return all the dates based on Saturday in the given range of start and end date.
Syntax:
d3.timeSaturdays(start, end, step);
Parameters: This function accept three parameters which are given below:
- Start: This is the given start date.
- end: This is the given end date.
- step: This is the optional value used to skip dates.
Return Value: This function returns all the dates based on Saturday.
Below programs illustrate the d3.timeSaturdays() function in D3.js:
Example 1:
<!DOCTYPE html> <html> <head> <title>
D3.js | d3.timeSaturdays() Function
</title>
<script src=
</script>
</head> <body> <script>
// Initialising start and end date
var start = new Date(2015, 07, 01);
var end = new Date(2015, 07, 30);
// Calling the timeSaturdays() function
// without step value
var a = d3.timeSaturdays(start, end);
// Getting the Saturday dates
console.log(a);
</script>
</body> </html> |
Output:
[“2015-07-31T18:30:00.000Z”, “2015-08-07T18:30:00.000Z”, “2015-08-14T18:30:00.000Z”, “2015-08-21T18:30:00.000Z”, “2015-08-28T18:30:00.000Z”]
Example 2:
<!DOCTYPE html> <html> <head> <title>
D3.js | d3.timeSaturdays() Function
</title>
<script src=
</script>
</head> <body> <script>
// Initialising start and end date
var start = new Date(2015, 07, 01);
var end = new Date(2015, 07, 30);
// Calling the timeSaturdays() function
// with step value
var a = d3.timeSaturdays(start, end, 2);
// Getting the Saturday dates
console.log(a);
</script>
</body> </html> |
Output:
["2015-07-31T18:30:00.000Z", "2015-08-14T18:30:00.000Z", "2015-08-28T18:30:00.000Z"]
Reference: https://devdocs.io/d3~5/d3-time#timeSaturdays