We are given an array of elements and we have to check the whether each element is even or not.
Examples:
Input : [2, 4, 6, 8, 9] Output : All the elements are not even Input : [4, 6, 8, 12, 14] Output : All the elements are even
Approach: The above problem can be solved using for loop but in C++ we have all_of() algorithm which operates on whole array and save time to write code for loop and checks each element for the specified property.
Note that all_of() also uses loop internally, it just saves our time of writing a loop code.
CPP
// CPP program to check if all elements // of an array are even or odd. #include <algorithm> #include <iostream> using namespace std;
void even_or_not( int arr[], int len)
{ // all_of() returns true if given operation is true
// for all elements, otherwise returns false.
all_of(arr, arr + len, []( int i) { return i % 2; }) ?
cout << "All are even elements" :
cout << "All are not even elements";
} int main()
{ int arr[] = { 2, 4, 6, 12, 14, 17 };
int len = sizeof (arr) / sizeof (arr[0]);
even_or_not(arr, len);
return 0;
} |
Output:
All are not even elements