What is the output of the following program?
#include <stdio.h> int main()
{ char check = 'a' ;
switch (check)
{
case 'a' || 1: printf ( "Geeks " );
case 'b' || 2: printf ( "Quiz " );
break ;
default : printf ( "GeeksQuiz" );
}
return 0;
} |
(A) Geeks
(B) Geeks Quiz
(C) Geeks Quiz GeeksQuiz
(D) Compile-time error
Answer: (D)
Explanation: An expression gets evaluated in a case label. Both the cases used are evaluated to 1(true). So compile-time error: duplicate case value is flashed as duplicated cases are not allowed.
Quiz of this Question