C/C++ program for Armstrong Numbers

Given a number N, the task is to check whether the given number is Armstrong number or not. If the given number is Armstrong Number then print “Yes” else print “No”.

A positive integer of D digits is called an armstrong-numbers of order D (order is the number of digits) if Where D is number of digit in number N and N(1), N(2), N(3)… are digit of number N.

Examples:

Input: N = 153 Output: Yes Explanation: 153 is an Armstrong number. 1*1*1 + 5*5*5 + 3*3*3 = 153 Input: 120 Output: No Explanation: 120 is not an Armstrong number. 1*1*1 + 2*2*2 + 0*0*0 = 9

Approach: The idea is to count the number of digits(say d) in the given number N. For every digit(say r) in the given number N find the value of r^d and if the summation of all the values is N then print “Yes” else print “No”. Below is the implementation of the above approach:

C

// C program to find Armstrong number
#include <stdio.h>

// Function to calculate N raised
// to the power D
int power(int N, unsigned int D)
{
    if (D == 0)
        return 1;

    if (D % 2 == 0)
        return power(N, D / 2)
               * power(N, D / 2);

    return N * power(N, D / 2)
           * power(N, D / 2);
}

// Function to calculate the order of
// the number
int order(int N)
{
    int r = 0;

    // For each digit
    while (N) {
        r++;
        N = N / 10;
    }
    return r;
}

// Function to check whether the given
// number is Armstrong number or not
int isArmstrong(int N)
{
    // Calling order function
    int D = order(N);

    int temp = N, sum = 0;

    // For each digit
    while (temp) {
        int Ni = temp % 10;
        sum += power(Ni, D);
        temp = temp / 10;
    }

    // If satisfies Armstrong condition
    if (sum == N)
        return 1;
    else
        return 0;
}

// Driver Code
int main()
{
    // Given Number N
    int N = 153;

    // Function Call
    if (isArmstrong(N) == 1)
        printf("True\n");
    else
        printf("False\n");
    return 0;
}

C++

// C++ program to find Armstrong number
#include <bits/stdc++.h>
using namespace std;

// Function to calculate N raised
// to the power D
int power(int N, unsigned int D)
{
    if (D == 0)
        return 1;

    if (D % 2 == 0)
        return power(N, D / 2)
               * power(N, D / 2);

    return N * power(N, D / 2)
           * power(N, D / 2);
}

// Function to calculate the order of
// the number
int order(int N)
{
    int r = 0;

    // For each digit
    while (N) {
        r++;
        N = N / 10;
    }
    return r;
}

// Function to check whether the given
// number is Armstrong number or not
int isArmstrong(int N)
{
    // To find order of N
    int D = order(N);

    int temp = N, sum = 0;

    // Traverse each digit
    while (temp) {
        int Ni = temp % 10;
        sum += power(Ni, D);
        temp = temp / 10;
    }

    // If satisfies Armstrong condition
    if (sum == N)
        return 1;
    else
        return 0;
}

// Driver Code
int main()
{
    // Given Number N
    int N = 153;

    // Function Call
    if (isArmstrong(N) == 1)
        cout << "True";
    else
        cout << "False";
    return 0;
}

Output:

True

Time Complexity:O(log₁₀N)Auxiliary Space:O(1)