In the automaton below, s is the start state and t is the only final state.
Consider the strings u = abbaba, v = bab, and w = aabb. Which of the following statements is true?
(A) The automaton accepts u and v but not w
(B) The automaton accepts each of u, v, and w
(C) The automaton rejects each of u, v, and w
(D) The automaton accepts u but rejects v and w
Answer: (D)
Explanation:
For the acceptance and rejection of any string we can simply check for the movement on each input alphabet between states. A string is accepted if we stop at any final state of the DFA.
For string u=abbaba the string ends at t (final state) hence it is accepted by the DFA.
For string v=bab the string ends at s (non-final state) and hence rejected by the DFA.
For string w=aabb the string ends at s (non-final state) and hence rejected by the DFA.
This solution is contributed by Yashika Arora.
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