In a fair game of Rock, Paper and Scissors, each player has an equal probability of winning, losing, or tying, resulting in a 1/3 (or approximately 33.33%) chance of winning.
In Rock, Paper, Scissors, each player can choose one of three possible moves: Rock, Paper, or Scissors. The outcome of the game is determined by the rules:
- Rock crushes Scissors.
- Scissors cuts Paper.
- Paper covers Rock.
Now, let’s consider the probability of winning for a single move:
Probability of winning with Rock (P(R)):
- Rock wins against Scissors but loses to Paper.
- There is one favorable outcome (winning against Scissors) out of three possible outcomes (Scissors, Paper, Rock).
- P(R) = 1/3.
Probability of winning with Paper (P(P)):
- Paper wins against Rock but loses to Scissors.
- There is one favorable outcome (winning against Rock) out of three possible outcomes.
- P(P) = 1/3.
Probability of winning with Scissors (P(S)):
- Scissors win against Paper but lose to Rock.
- There is one favorable outcome (winning against Paper) out of three possible outcomes.
- P(S) = 1/3.
Therefore, for each move (Rock, Paper, or Scissors), the probability of winning is 1/3.