Given i= 0, j = 1, k = – 1
x = 0.5, y = 0.0
What is the output of given ‘C’ expression ?
x * 3 & & 3 || j | k
(A) -1
(B) 0
(C) 1
(D) 2
Answer: (C)
Explanation: According to given data:
x * 3 && 3 || j | k = 1.5 && 3 || j | k = 1 || j |k = 1
So, option (C) is correct.
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