Result of sizeof operator

Predict the output of below program.

#include <stdio.h>
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {1, 2, 3, 4, 5, 6, 7};

int main()
{
 int i;

 for(i = -1; i <= (TOTAL_ELEMENTS-2); i++)
   printf("%d\n", array[i+1]);

 getchar();
 return 0;
}

Output: Nothing is printed as loop condition is not true for the first time itself.

The result of sizeof for an array operand is number of elements in the array multiplied by size of an element in bytes. So value of the expression TOTAL_ELEMENTS in the above program is 7.
The data type of the sizeof result is unsigned int or unsigned long depending upon the compiler implementation. Therefore, in the loop condition i